21. Refer to the illustration above. The child represented in box 1 in the Punnett square would
a. be homozygous for freckles.
C. be heterozygous for freckles.
b. have an extra freckles chromosome. d. not have freckles.

A.

Explanation:

We can see that in both the male and female despite being heterozygous both have freckles. This must mean that freckles is a dominant trait. In box one, there are two capital f's (FF). Two of the same would make it homozygous, and because it is two of the dominant trait which gives freckles A is the correct choice.