A blue-eyed myopic woman from a marriage with a brown-eyed man with normal vision gave birth to a brown-
eyed myopic girl and a blue-eyed boy with normal vision. The gene for myopia (B) is dominant over the gene for
normal vision (c), and the gene for brown eyes (C) is dominant over the gene for blue eyes (c). What is the
probability of the birth in this family of a brown-eyed child with normal vision?
Выберите один ответ:
a. 50%
O b. 75%
c. 0%
O d. 25%
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Ответ:
option b 75%
Explanation:
this is the answer I guess
Ответ:
The answer is option B 75%
Explanation:
The probability of birth of a brown-eyed child with normal vision is 75%
thank you.
Ответ: