A child develops symptoms of chicken pox, produces antibodies against its specific antigens, and recovers from the illness. Later as an adult, he is immune to another exposure to the chicken pox virus. This is an example of which type of immunity

1.54 L

Explanation:

Camels use water obtained from the process of cellular respiration when they use fats as a substrate.

Suppose the fat used during respiration is Tripalmitoylglycerol which contains 3 palmitic acid or Palmitoyl-CoA attached to the esters.

The molecular weight of Tripalmitate is 807 g/mol  therefore 1000 g of fat will have 1000/807 = 1.24 moles of Tripalmitate x 3 = 3.72 moles of Palmitoyl CoA.

Now according to the Beta oxidation reaction,

Palmitoyl CoA + 23 O₂+ 108 ADP + 108 Pi > 16 CO₂ + 108 ATP + 23 H₂O + 8 Acetyl CoA

1.23 moles of  Palmitoyl CoA produce 23 H₂O therefore  

3.72 will produce Palmitoyl CoA will produce= 3.72 x 23 H₂O

= 85.56 H₂O molecules.

Now, 85.56 H₂O molecules will yield

= 85.56 x 18                       ( MW of water=18)

= 1541.8 g

= 1.54 L

Thus, 1.54 L is correct.