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elmoreroman11
17.11.2019 •
Biology
A7 l sample of gas has a pressure of 1.1 atm at a temperature of 285 k. if the pressure decreases to 0.6 atm, causing the volume to increase to 10 l, what is the new temperature? round your answer to the nearest tenth.
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Ответ:
Gay-Lussac’s law:
PV = kT
P - pressure
V - volume
T - temperature
k - constant
k = PV/T = P1 * V1 / T1 = P2 * V2 / T2 = ...
P1 * V1 / T1 = P2 * V2 / T2
P1 = 1.1 atm
V1 = 7 L
T1 = 285 K
P2 = 1.1 atm - 0.6 atm = 0.5 atm
V2 = 7 L + 10 L = 17 L
T2 = ?
1.1 * 7 / 285 = 0.5 * 17 / T2
7.7 / 285 = 8.5 / T2
T2 = 8.5 * 285 / 7.7
T2 = 314.6 K
Ответ:
Given:
width = 8 cm
length = 310 cm
height = 0.40 cm
cost = $0.015 per cm³
Volume of a rectangular prism is solved by multiplying its length, its width, and its height.
V = l * w * h
= 310 cm * 8 cm * 0.40 cm
V = 992 cm³
Total cost = Volume * cost per cm³
= 992 cm³ * $0.015/cm³
Total cost = $14.88