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jocelyn7575
23.12.2020 •
Biology
E. coli strain B is doubly infected with two rII mutants of phage T4. 0.2 ml of a 108 dilution of the progeny is plated on E. coli B and 0.1 ml of a 104 dilution of the progeny is plated on E. coli K. 16 plaques appeared on strain B, 400 on strain K. Calculate the recombination frequency between these two mutations.
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Ответ:
Given:
No. of mutation = 2Volume,The formula:
→![R.F = No. \ of \ mutations\times \frac{No. \ of \ k \ plaques\times D.F }{Volume}\times \frac{Volume'}{No. \ of \ B \ plaques\times D.F'}](/tpl/images/1006/6485/3ec4b.png)
By putting the values in the above formula, we get
→![= \frac{2\times 400\times 0.2\times 10^4}{16\times 0.1\times 10^8}](/tpl/images/1006/6485/d7bc1.png)
→![= \frac{160\times 10^4}{1.6\times 10^8}](/tpl/images/1006/6485/88f95.png)
→![= 0.01](/tpl/images/1006/6485/7ffb5.png)
Thus the solution above is the right approach.
Learn more about frequency here:
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Ответ:
To Find :
The recombination frequency between these two mutations.
Solution :
Formula of calculating recombination frequency is :
Putting all given values in above equation, we get :
Therefore, the recombination frequency between these two mutations is 0.01 or 1 %.
Ответ:
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