Female iii-4 is pregnant via male iii-5. the owner of this breeding pair wants to know the probabilities of several possible outcomes for their offspring (iv-3). answer each question by dragging the correct label to the appropriate location. labels can be used once, more than once, or not at all.

We can say that female 111-4 is being pregnant to a male 111-5. The breeding owner of this pairs wants to know various outcomes for their iv-3(offsprings). Let's say we have condition A and condition B. The probability that iv-3 will have condition A is one out of thirty-six (1/36).
The probability that iv-3 will have condition B is one out of eight (1/8).Then the probability that iv-3 will have both conditions A and B is 1/288.We have 245/288 that iv-3 will have neither probability at all. We can also say the probability that iv-3 will have either one of the two conditions is 43/288.

The answer to yo question is D