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saabrrinnaaa
28.12.2019 •
Biology
In humans, syndactyly (webbed digits) is inherited by possession of a dominant allele (s). if a man who is homozygous and normal digits (55) marries a woman who is heterozygous for syndactul and has webbed diaits, what percentage of their children would be expected to have webbed digits?
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Ответ:
The % of children with webbed digits is
%
Explanation:
Given -
Syndactyly or webbed digits are due to the presence of a dominant allele (S). Then the allele for normal digits would be represented by allele "s"
A normal man with normal digits and genotype "ss" marries a woman with webbed digits and has a hetrozygous genotype i.e "Ss"
If we cross Ss and ss , then the following offspring are produced -
Ss * ss
Ss, Ss, ss, ss
Out of four 2 offspring with genotype ss have normal digits and remaining two offspring with genotype "Ss" have webbed digits. Thus, the % of children with webbed digits is
%
Ответ: