In rabbits, the fur color and ear position are two genetic traits. each trait is located on separate chromosomes. the allele for producing brown fur (b) is dominant to the allele for producing white fur (b). the allele for producing straight ears (e) is dominant to the allele for producing floppy ears (e). what are the possible genotypes for a rabbit with white fur and straight ears? a) bbee, bbee, bbee and bbee b) bbee, bbee c) bbee, bbee d) bbee, bbee

The map distance between sn and ct is = 25 m.u or map unit.

Explanation:

Given, sn ct+  ×  sn+ ct

In F1 generation the progenies were interbred.

In F2 generation,

sn ct = 13  (recombinant)

sn ct+ = 36  (parental)

sn+ ct = 39  (parental)

sn+ ct+ = 12 (recombinant)

Linkage Map distance = (no. of Recombinant progeny/total progeny)  

                                                                                                                     × 100                              

Recombination frequency = (no. of Recombinant progeny/total progeny)                              

                                                                                                                    × 100

                                            = ( 13+ 12) /100 × 100 m.u

                                             = 25/100  × 100

                                              = 25 %                                      

∴ The distance between sn and ct  = 25 m.u or map unit

∴  Linkage happened  between sn and ct as the map distance is much less than 50