Suppose you have the monohybrid pea plants in your garden and find that they produce round seed to wrinkled seeds in the ration 3: 1. if the allele are designated (r & r) respectively, what is the probably genotypes of the rounds seeds with were produced?

Answer;

The correct answer would be Rr.

In a monohybrid cross, the phenotype ratio of 3:1 is obtained only when both the parents are heterozygous for the trait.

In this condition, the heterozygous genotype would be Rr. The phenotype of both the parents would be round seeds (R) as the round is a dominant trait.

The cross of these parents would produce offspring with three types of genotypes RR, Rr, and rr in ratio 1:2:1.

Thus, the phenotypic ratio would come out to be 3 (round seed):1 (wrinkled seed).

The majority of gas exchange in plants takes place through leaves. They contain structures called as stomata, which are pores formed between guard cells. These openings allow the exchange of oxygen and carbon dioxide between plants and the surrounding atmosphere. Apart from leaves, openings are also present on stem and they are termed as lenticels. Small proportion of gas exchange takes place through stem also.