![foriegnngal](/avatars/31589.jpg)
foriegnngal
11.10.2019 •
Business
An example of capital deepening would be?
a. permitting two workers to share one job.
b. paying for an employee to take college courses.
c. laying off employees when a factory is modernized.
d. moving a manufacturing plant overseas where labor costs lower.
Solved
Show answers
More tips
- G Goods and services How to choose a washing machine?...
- F Family and Home Is it Worth Knowing the Gender of Your Child Before Birth?...
- H Health and Medicine Mercury Thermometer Danger: What to do when a thermometer breaks?...
- F Food and Cooking How to cook crayfish? Everything you need to know...
- G Goods and services LED-подсветка в LCD-телевизорах: 5 причин, почему она лучше других технологий...
- P Photography and Videography Understanding HDR: How It Works and Why You Need It...
- G Goods and services Which TV is better - LCD or Plasma?...
- S Sport How to Learn to Pull Up on Monkey Bars?...
- L Leisure and Entertainment Scrapbooking: What is it and Why is it Becoming More Popular?...
Answers on questions: Business
- B Business Curtis Corporation s noncallable bonds currently sell for $1,165. They have a 15-year maturity, an annual coupon of $95, and a par value of $1,000. What is their yield to maturity...
- B Business A company purchased equipment and signed a 5-year installment loan at 10% annual interest. The annual payments equal $11,600. The present value of an annuity factor for 5 years...
- B Business 7-13 After-Tax PW of an Asset The asset in Example 7-12 is expected to produce net cash inflows (net revenues) of $30,000 per year during the six-year period, and its terminal...
- B Business In 2019, George and Martha are married and file a joint tax return claiming their two children, ages 10 and 8 as dependents. Assuming their AGI is $119,650, George and Martha...
- B Business Bond J has a coupon rate of 4.2 percent. Bond S has a coupon rate of 14.2 percent. Both bonds have ten years to maturity, make semiannual payments, a par value of $1,000, and...
- B Business can encourage employee commitment to the core purpose of an organization, its specific goals, and the basic means used to accomplish goals. It can determine how the organization...
- B Business Rusty Industries has decided to save $50,000 a year for two years and then increase that amount to $80,000 for an additional three years. Which one of these formulas will correctly...
- B Business Prepare a paper and summarize key developments in macroeconomic history. Specifically, what are the similarities and differences between Keynesian and classical economics? How...
- B Business A trade discount is: Question 52 options: A term used by a purchaser to describe a cash discount given to customers for prompt payment. A reduction in selling price below the...
- B Business Weiland Co. shows the following information on its 2019 income statement: sales = $162,500; costs = $80,000; other expenses = $3,300; depreciation expense = $9,000; interest...
Ответ:
b
the correct answer is actually paying for an employee to take college courses
hope this helped
Ответ:
Question:
A piston–cylinder device contains 0.85 kg of refrigerant- 134a at -10°C. The piston that is free to move has a mass of 12 kg and a diameter of 25 cm. The local atmospheric pressure is 88 kPa. Now, heat is transferred to refrigerant-134a until the temperature is 15°C. Determine (a) the final pressure, (b) the change in the volume of the cylinder, and (c) the change in the enthalpy of the refrigerant-134a.
a) 90.4 kPa
b) 0.0205 m³
c) 17.4 kJ/kg
Explanation:
Given:
Mass, m = 0.85 kg
a) The final pressure here is equal to the initial pressure. Let's use the formula:
= 90398 Pa
≈ 90.4 KPa
Final pressure = 90.4 kPa
b) Change in volume of the cylinder:
To find the initial and final volume, let's use the values from the A-13 table for refrigerant-134a, at initial values of 90.4 kPa and -10°C and final values of 90.4 kPa and 15°C
v1 = 0.2302m³/kg
h1 = 247.76 kJ/kg
v2 = 0.2544 m³/kg
h2 = 268.2 kJ/kg
Change in volume is calculated as:
Δv = m(v2 - v1)
Δv = 0.85(0.2544 - 0.2302)
= 0.0205 m³
Change in volume = 0.0205 m³
c) Change in enthalpy
Let's use the formula:
Δh = m(h2 - h1)
= 0.85(268.2 - 247.76)
= 17.4 kJ/kg
Change in enthalpy = 17.4 kJ/kg