Business: Astatement of an employee s biweekly earnings is given below. earnings deductions week ended regular fed. soc. med state with. with. care. with. net pay 9/10 $ $98.00 $52.88 $12.37 $22.54 $667.17 what is the employee s gross pay? a. $818.05 b. $830.42 c. $840.59 d. $852.96 select the best answer from the choices provided a b c d

Astatement of an employee s biweekly earnings is

dj129239

06.01.2022

if I had the *table* I would choose

D. d. $852.96

Explanation:

(why did this guy not add the table?)

You need the table to show why it is D.

here is a representation

sorry i am new to

Earnings | Deductions

Week Ended | Regular || FED. || SOC. || MED || STATE || NET PAY

| WITH. || WITH. || CARE. || WITH.

9/10 | $ || $98.00 || $52.88 || $12.37 || $22.54 | $667.17

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potatogirl9300

01.02.2022

Step-by-step explanation:

h(t) = (t + 3)² + 5

A) h(t) = (t + 3)² + 5 -2 ≤ t ≤ 0

average rate of change in h over the change in t is given as:

$\frac{h(0)-h(-2)}{0-(-2)}=\frac{(0+3)^2+5-[(-2+3)^2+5]}{0+2}=\frac{14-6}{2} =4$

It does not have a negative average rate of change

B) A) h(t) = (t + 3)² + 5 -4 ≤ t ≤ -3

average rate of change in h over the change in t is given as:

$\frac{h(-3)-h(-4)}{-3-(-4)}=\frac{(-3+3)^2+5-[(-4+3)^2+5]}{-3+4}=\frac{5-6}{1} =-1$

It have a negative average rate of change

c) A) h(t) = (t + 3)² + 5 -3 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(-3)}{4-(-3)}=\frac{(4+3)^2+5-[(-3+3)^2+5]}{4+3}=\frac{54-5}{7} =7$

It does not have a negative average rate of change

D) h(t) = (t + 3)² + 5 1 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(1)}{4-(1)}=\frac{(4+3)^2+5-[(1+3)^2+5]}{4-1}=\frac{54-21}{3} =11$

It does not have a negative average rate of change

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