Chemistry: 0 / 5 pts Question 3 In the reaction of aluminum with iron III oxide, if you start with 54.2 grams of aluminum, how many grams of iron III oxide are needed for the reaction to occur?

0 / 5 pts Question 3 In the reaction of aluminum with

Ответ:

naynay4evr

14.02.2022

Could you please mark me as brainliest?

160.40 g Fe2O3 are needed.

Explanation:

Balanced equation: 2 Al + Fe2O3 —> Al2O3 + 2Fe

54.2 g Al * 1 mol Al / 26.98 g Al * 1 mol Fe2O3 / 2 mol Al * 159.69 g Fe2O3 / 1 mol = 160.40 g Fe2O3 are needed.

0,0(0 оценок)

Ответ:

cassiegagnier73

05.02.2023

Chemistry

Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²

Further explanation

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

1 dm³ of oxygen = 1 L Oxygen

mol Oxygen :

$\tt \dfrac{1}{22.4}=0.045`mol$

molecules of Oxygen :

n=mol=0.045

No = 6.02.10²³

$\tt N=n\times No\\\\N=0.045\times 6.02\times 10^{23}\\\\N=2.71\times 10^{22}$

0,0(0 оценок)

0 / 5 pts Question 3 In the reaction of aluminum with iron III oxide, if you start with 54.2 grams of aluminum, how many grams of iron III oxide are needed for the reaction to occur?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question