1. Calculate the [H] in a solution that has a pH of 9.88.
A) 4.1 M
B) 9.9 M
C) 7.6 x 10'M
D) 1.3 x 10 "M
E) none of these

The answer to your question is the letter D) [H⁺] = 1.3 x 10⁻¹⁰ M

Explanation:

Data

[H⁺] = ?

pH = 9.88

pH measures the [H⁺] in a solution. It has a range from 0 to 14. Acids have a pH from 0 to 6.9, a neutral solution has a pH of 7.0 and alkalis have a pH from 7.1 to 14.

Formula

pH = -log [H⁺]

Substitution

9.88 = -log[H⁺]

Simplification

antilog -9.88 = [H⁺]

-Result

[H⁺] = 1.3 x 10⁻¹⁰ M