Kjcampbell2
11.07.2021 •
Chemistry
1 mole of alkene CxH2x was fully burnt in oxygen. The products were analysed. 264g of Co2 and 108g of of H20 were produced. Use the information to balance the equation and work out the identity of CxH2x.
CxH2x+ O2--> CO2+H2O
PLEASE CAN SOMEONE EXPLAIN THIS TO ME
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Ответ:
C6H12
Explanation:
Step 1: Find the molar mass of carbon dioxide and water
MH2O = 2(1.008) + 16.00 = 1.802x10^1 g/mol
MCO2 = 12.01 + 2(16.00) = 4.401x10^1 g/mol
Step 2: Calculate the moles of the products
nH2O = 108g / 1.802x10^1 g/mol = 5.99 or about 6
nCO2 = 264g/ 4.401x10^1 g/mol = 5.99 or about 6
Step 3: Enter moles of carbon dioxide and water into the balanced equation
CxH2x + O2 = 6CO2 + 6H2O
Step 4: Balance
We see how there is six carbon dioxide on the right side which means there are six carbons in the equation.
This means x is equal to 6 in our equation.
If you plug the information into the equation you get:
C6H12 + O2 = 6 CO2 + 6 H2O
Now all that's left is to balance the oxygens
We see how there is 18 oxygens on the right side of the equation which means there must be 18 on the left side.
Because we have oxygen gas we divide 18 by 2 which means there are 9 O2's on the left side
Therefore, the balanced equation is C6H12 + 9O2 = 6 CO2 + 6 H2O
Ответ:
15.17 g
Explanation:
To answer this, we need to find the molar mass of nickel in nickel (II) fluoride. The formula for nickel (II) fluoride is NiF2. This gives us the molar mass of 96.69 g. The mass percentage of nickel is 60.70% approximately (as we divide the molar mass of nickel by that of nickel (II) fluoride), and 60% of 25g gives us 15.17 g