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izeahzapata1
20.09.2020 •
Chemistry
1) Use the Born-Haber cycle and given data ΔH∘fKCl = -436.5 kJ/mol, IE1(K) = 419 kJ/mol, ΔHsub(K)=89.0 kJ/mol, Cl2(g)bondenergy = 243 kJ/mol, EA(Cl) = -349 kJ/mol to calculate the lattice energy of KCl. 2) Use the Born-Haber cycle and data from Appendix IIB and Table 9.3 in the textbook to calculate the lattice energy of CaO. You may need the following data: electron affinity of oxygen EA1=−141kJ/mol, EA2=744kJ/mol; ionization energy of calcium IE1=590kJ/mol, IE2=1145kJ/mol, the enthalpy of sublimation for calcium ΔHsub=178kJ/mol.
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Ответ:
Explanation:
1 ) Let the lattice energy per mole be x
2 K + Cl₂ = 2KCl
Applying Born- Haber cycle
2 x 89 + 2 x 419 + 243 - 2 x 349 + Δx = - 2 x 436.5
178 + 838+ 243 - 698 + Δx = - 873
Δx = 1434 kJ
Lattice energy per mole = 1434 / 2 = 717 kJ / mol
2 )
2Ca + O₂ = 2 CaO
Heat of formation of CaO = - 635 kJ
Let lattice energy be x / mol
Bond energy of oxygen = 498 kJ / mol
178 x 2 + 2 ( 590 + 1145 ) + 498 + 2 ( 744 - 141 ) + x = - 2 x 635
356 + 3470 + 1206 + 498 + 2 x = - 1270
5530 + 2 x = - 1270
x = - 3400 kJ
Ответ:
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