Chemistry: 10.0 ml of a 0.770 m sodium hydroxide solution is transferred to a 50.0 ml volumetric flask followed by the addition of water to the calibration mark. what is the new concentration of the sodium hydroxide solution?

We just need to do come computation:So, we have 34 28...

10.0 ml of a 0.770 m sodium hydroxide solution is

babygirl091502

11.01.2022

The new concentration of the sodium hydroxide solution = 0.154 M

Explanation:

Considering :-

$Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}$

Given that:

$Molarity_{1}=0.770\ M$

$Volume_{1}=10.0\ mL$

$Volume_{2}=50.0\ mL$

$Molarity_{2}=?$

So,

$Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}$

$0.770\ M\times 10.0\ mL=Molarity_{2}\times 50.0\ mL$

$Molarity_2=\frac{0.770\times 10.0}{50.0}\ M=0.154\ M$

The new concentration of the sodium hydroxide solution = 0.154 M

0,0(0 оценок)

comeonmanim

20.11.2021

We just need to do come computation:

40-16+10 = 40+(-16+10) = 40+(-6) = 40-6=34

-20+18+30 = -2+30 = 28

So, we have 34>28

0,0(0 оценок)