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kylemartinez13
08.04.2020 •
Chemistry
14. In the lab, an experimenter mixes 75.0 g of water (initially at 30oC) with 83.8 g of a solid metal (initially at 600oC). At thermal equilibrium, he measures a final temperature of 50.0oC. What metal did the experimenter probably use
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Ответ:
Tungsten is used for this experiment
Explanation:
This is a Thermal - equilibrium situation. we can use the equation.
Loss of Heat of the Metal = Gain of Heat by the Water
Q = mΔT![C_{p}](/tpl/images/0588/5013/9670a.png)
Q = heat
m = mass
ΔT = T₂ - T₁
T₂ = final temperature
T₁ = Initial temperature
Cp = Specific heat capacity
Metal
m = 83.8 g
T₂ = 50⁰C
T₁ = 600⁰C
Cp =![x](/tpl/images/0588/5013/a0e3f.png)
Water
m = 75 g
T₂ = 50⁰C
T₁ = 30⁰C
Cp = 4.184 j.g⁻¹.⁰c⁻¹
⇒ - 83.8 x
x (50 - 600) = 75 x 4.184 x (50 - 30)
⇒
=
j.g⁻¹.⁰c⁻¹
We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹
So metal Tungsten used in this experiment
Ответ: