149.3 g of h2o at 95 ◦c is poured over 412 g fe at 5 ◦c in an insulated vessel. what is the final temperature? the specific heat of h2o is 4.184 j /g· ◦c, the specific heat of fe is 0.444 j/g · ◦c. answer in units of ◦c.
i believe i am supposed to use the equation -q=q, where each q=mc(change in t). but how do i know whether the water or the iron is the negative q?
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Ответ:
-149.3 * 4.184 * (T - 95) = 412 * 0.44 * (T - 5)
Solving this equation for T,
T = 74.8 °C
Ответ:
Answer is in the file below
cutt.ly/nz6VGda