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babysisjessica1
14.01.2020 •
Chemistry
2)
if 5.0 moles of o2 and 3.0 moles of n2 are placed in a 30.0 l tank at a temperature of 25°
c, what will the pressure of the resulting mixture of gases be?
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Ответ:
Total pressure = 6.55 atm
Explanation:
Given data:
Number of moles of oxygen = 5.0 mol
Number of moles of nitrogen = 3.0 mol
Volume of tank = 30.0 L
Temperature = 25°C (25+273 = 298 K)
Total pressure of mixture = ?
Solution:
Pressure of oxygen:
PV = nRT
P = nRT/V
P = 5.0 mol ×0.0821 atm.L/mol.K × 298 k /30.0 L
P = 122.33 atm /30.0
P = 4.1 atm
Pressure of nitrogen:
PV = nRT
P = nRT/V
P = 3.0 mol ×0.0821 atm.L/mol.K × 298 k /30.0 L
P = 73.4 atm /30.0
P = 2.45 atm
Total pressure = Partial pressure of oxygen + partial pressure of nitrogen
Total pressure = 4.1 atm + 2.45 atm
Total pressure = 6.55 atm
Ответ: