Chemistry: 250 g H 2 SO 4 completely reacted with aluminum? 2AI(s) + 32504(aq)- AI2 (504) 3(aq) + 3H 2 (9) 0.85g 450g 290g 870g

250 g H 2 SO 4 completely reacted with aluminum?

shateece

30.01.2022

290 g of aluminium sulphate is produced.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} H_2SO_4=\frac{250g}{98g/mol}=2.55moles$

The balanced chemical reaction is:

$2Al(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2(g)$

According to stoichiometry :

3 moles of H_2SO_4 produce = 1 mole of Al_2(SO_4)_3

Thus 2.55 moles of H_2SO_4 will require= $\frac{1}{3}\times 2.55=0.85moles$ of Al_2(SO_4)_3

Mass of $Al_2(SO_4)_3=moles\times {\text {Molar mass}}=0.85moles\times 342g/mol=290g$

Thus 290 g of aluminium sulphate is produced.

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kaleahearly123

07.06.2020

Ca scans scan sk wo wka d Turkey show alone kar s

Explanation:

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