29.5 g of mercury is heated from 32°c to 161°c, and absorbs 499.2 joules of heat in the process. calculate the specific heat capacity of mercury (in jg°c).
Solved
Show answers
More tips
- C Computers and Internet Step-by-Step Guide on How to Download Music to Your iPhone...
- A Animals and plants Unraveling the Mystery of Loch Ness: What Does the Loch Ness Monster Look Like?...
- L Leisure and Entertainment Should You Buy a Ceramic Knife?...
- C Computers and Internet How to easily and quickly disable Firebug in Gmail and Google Docs...
- G Goods and services How to sew a ribbon: Tips for beginners...
- F Food and Cooking How to Make Mayonnaise at Home? Secrets of Homemade Mayonnaise...
- C Computers and Internet Which Phone is Best for Internet Surfing?...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
Answers on questions: Chemistry
- M Mathematics If the area of the rectangle below is 84 feet squared, find the value of x....
- M Mathematics 27. Evaluate the expression 4a? when a = 6 and b = 36. Show your work....
- E English Which word from this sentence is an academic word? analyze the passage below and talk about the photographer s use of exposure exposure analyze photographer s talk...
- E English Select the correct text in the passage. Which sentence in this except from Mark Twain s The Adventures of Tom Sawyer shows Tom to be resourceful? Monday morning...
Ответ:
c = 0.13 j/ g.°C
Explanation:
Given data:
Mass of mercury = 29.5 g
Initial temperature = 32°C
Final temperature = 161°C
Heat absorbed = 499.2 j
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = m.c. ΔT
ΔT = T2 - T1
ΔT = 161°C - 32°C
ΔT = 129 °C
Q = m.c. ΔT
c = Q / m. ΔT
c = 499.2 j / 29.5 g. 129 °C
c = 499.2 j / 3805.5 g. °C
c = 0.13 j/ g.°C
Ответ:
I know the answer
Explanation: