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trejoarmando061
24.03.2020 •
Chemistry
2Cl(g) ⇌ Cl2(g)
Calculate the ΔH, ΔS and ΔSuniverse for this reaction.
Determine the spontaneity of the reaction.
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Ответ:
-121.301 kJ·mol⁻¹; 57.8 J·K⁻¹mol⁻¹; 464.9 J·K⁻¹mol⁻¹; spontaneous
Explanation:
2Cl(g) ⇌ Cl₂(g)
ΔHf°/kJ·mol⁻¹: 121.301 0
S°/J·K⁻¹mol⁻¹: 165.190 223.0
1. ΔᵣH
ΔᵣH = products -reactants = 0 - 121.301 = -121.301 kJ·mol⁻¹
2. ΔᵣS
ΔᵣS = products - reactants = 223.0 - 165.190 = 57.8 J·K⁻¹mol⁻¹
3. ΔS(univ)
4. Spontaneity
ΔG is negative, so the reaction is spontaneous.
Ответ:
The equation is y = $72.99 + $28.45(x - 1), where y is the monthly charge and x is the month in which it is calculated.
Step-by-step explanation:
Step 1; First we need to establish a relation between the difference in costs. For the first month it cost $72.99, during the second month, it costs $101.44 and in the third month, it costs $129.89. Difference in rates
Second months rate - First months rate = $101.44 - $72.99 = $28.45
Third months rate - Second months rate = $129.89 - $101.44 = $28.45.
So for every consecutive month, the charges increase by $28.45
Step 2; Now we develop an equation,
y = $72.99 + $28.45(x - 1), where y is the charge that month and x is the month in which it is calculated.
For x = 1, y = $72.99 + $28.45(1 - 1) = $72.99 + $28.45(0) = $72.99,
For x = 2, y = $72.99 + $28.45(x - 1) = $72.99 + $28.45(2 - 1) = $101.44,
For x = 3, y = $72.99 + $28.45(3 - 1) = $72.99 + $28.45(3-1) = $129.89.
So this is the equation to calculate the cost y the mobile provider charges in month x.