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17.01.2022 •
Chemistry
2H2O(I) ► O2(g) + 2H2(g)
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Ответ:
Ответ:
The molecular formula of the compound is C4H12O4.
π = icRT
π = osmotic pressure
c = concentration
R = molar constant
T = temperature
Now we know that; c = n/V
n = number of moles
V = volume
π = i(n/V)RT
π =inRT/V
n = πV/iRT
n = 2.13 atm × 0.175 L/1 × 0.082 atmLK-1mol-1 × 298 K
n = 0.3675/24.436
n = 0.015 moles
number of moles = mass/molar mass
Molar mass = mass/ number of moles = 2.04 g /0.015 moles = 136 g/mol
From the combustion information;
mass of C = 36.26 g/44 × 12 = 9.9 g
Number of moles of C = 9.9 g/12 g/mol = 0.825 moles
Mass of H = 14.85 g/18 × 2 = 1.65 g
Number of moles of H = 1.65 g/ 1 g/mol = 1.65 moles
Mass of O = 22.08 g - (9.9 g + 1.65 g) = 10.53 g
Number of moles of oxygen = 10.53 g/16 g/mol = 0.658 moles
To obtain the empirical formula, we divide through by the least number of moles;
C - 0.825 moles/0.658 moles, H - 1.65 moles/0.658 moles, O - 0.658 moles/0.658 moles
C - 1, H - 3, O - 1
The empirical formula of the compound is CH3O
The molecular formula of the compound is obtained thus;
[12 + 3 + 16]n = 136
n = 136/31
n = 4
The molecular formula is C4H12O4.
Learn more about molecular formula: link