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dakotacsey03
30.03.2020 •
Chemistry
3. Sulfite is a compound frequently added to preserve food and wine. In addition to inhibiting bacteria, it also prevents the oxidation of ethanol into acetic acid! a. It was previously discussed that sulfate, SO4 2– , can be categorized as a negligible base. Sulfite, SO3 2– , however, is basic. Considering the two structures, why is sulfite significantly more basic? b. Write the chemical equation and the equilibrium constant expression for the reaction between SO3 2– and water. c. Sulfurous acid, H2SO3 has a Ka1 = 1.23 x 10–2 and a Ka2 = 6.60 x 10–8 at 25 ºC. What is the pH of a 0.50M solution of Na2SO3?
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Ответ:
a) The detailed explanation for the question being asked in section a is shown below
b)![SO_3^{2-}_{(aq)} \ \ \ + H_2O_{l} ------ HSO_3^-_{(aq)} + OH^-](/tpl/images/0571/3193/67e3c.png)
Equilibrium constant expression![K_c = \frac{[HSO_3^-][OH^-]}{]SO_3^{2-}]}](/tpl/images/0571/3193/afa55.png)
c) pH = 10.45
Explanation:
a.
If we look at
, we will realize that it is a conjugate base of a strong acid
. However, the more stronger the acid, the weaker its conjugate base.
On the other hand
is a conjugate base of a weak acid
and the more weaker the acid, the stronger the basicity of its conjugate base.
b. The chemical equation for the reaction between
and water can be expressed as follows:
Equilibrium constant![K_c = \frac{[HSO_3^-][OH^-]}{]SO_3^{2-}]}](/tpl/images/0571/3193/afa55.png)
c.
The ICE Table is then constructed as follows:
Initial (M) 0.500 0 0
Change (M) - x + x + x
Equilibrium (M) (0.500 - x) x x
where
is the ionic product of water = ![10^{-14}](/tpl/images/0571/3193/576a9.png)
However;
pH + pOH = 14
pH + 3.55 = 14
pH = 14 - 3.55
pH = 10.45
Ответ:
50.0g C6H12O6 in 250g