3. The specific heat capacity of the metal the pot is made of is much lower than the specific heat capacity of water. Will the final temperature of the pot be closer to the initial temperature of the pot, the initial temperature of the water, or exactly halfway between the two? Explain your reasoning.

Explanation:

In calorimetry we apply the formula

heat lost = heat gained

m₁ x s₁ t ₁ = m₂ x s₂ t ₂

here t₁ and t₂ are change in temperature . suppose s₁ denotes specific heat of metal  a nd s₂ denotes specific heat of water .

If s₁ is far less than s₂ , t₁ will be far more than t₂ , to balance the two sides

Hence change in temperature of metal pot will be more than change in temperature of water.

Final temperature will be far away from temperature of the metal pot.

Final temperature will be closer to temperature of water.

1.55 moles if i am correct.