31.5 grams of an unknown substance is heated to 102.4 degrees celsius and then placed into a calorimeter containing 103.5 grams of water at 24.5 degrees celsius. if the final temperature reached in the calorimeter is 32.5 degrees celsius, what is the specific heat of the unknown substance?

show or explain the work needed to solve this problem, and remember that the specific heat capacity of water is 4.18 j/(°c x g). (2 points)

Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1) 

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. From this, we can calculate things. We do as follows:

Heat gained = Heat lost
mC(T2-T1) = - mC(T2-T1) 
31.5C (102.4 - 32.5) = 103.5(4.18)(32.5 - 24.5)
C = 1.57 J/C-g

Hope this helps.

Because of the unique property of carbon in which it can bind to many elements including itself, there are a variety of organic compounds. For long chains of organic compounds like nucleotides, polysaccharides and proteins, their basic building block are nucleic acids, sugars and amino acids, respectively. The general structure of nucleotides has a base sugar, a nitrogenous base and a phosphate group. For polysachharides and protein, the sugars and amino acids are linked together, respectively. The biological function of nucleotides is to carry the genetic information and help build proteins. Polysaccharides and proteins are needed by the body to do processes for metabolism.