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Juancr4539
16.02.2020 •
Chemistry
4) How many grams of F2, gas occupy 4.9 L at STP?
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Ответ:
We know two equations that can help as
n = m/Mr
"n" --> number of moles"m" --> mass (kg)"Mr" --> molecular mass of the substancen = V/Vm
"V" --> volume of gas"Vm" --> a constant which value is 22.4 for STP conditionsSo, combining the two equations above:
m/Mr = V/Vm
m = V×Mr/Vm
V = 4.9LMr = 38 *Vm = 22.4m = 8.31 gr
*To calculate the Mr of "F2" we need to multiply by 2 the atomic mass of F, which we can find onlu by looking it up in a table (probaly in the back of a chemistry book, or online). We see that it is equal to 19, so Mr will be equal to 38.
**The equations are derived easily. Lets take for example the first one. 1 mole of the substance contains Mr gr of it. So, how many gr do "n" moles contain?
Ответ:
8.31g
Explanation:
First, we calculate the molar mass of F2.
MM of F2 = 2 x 19 = 38g/mol
But,
1mol of a gas occupy 22.4L at stp.
This implies that 1mole(i.e 38g) of F2 occupies 22.4L.
Therefore, Xg of F2 will occupy 4.9L i.e
Xg of F2 = (38 x 4.9) / 22.4
Xg of F2 = 8.31g
Therefore 8.31g of F2 occupies 4.9L
Ответ:
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I hope this helps :)