4 NH3 + 5 O2 ---> 4 NO + 6 H2O How many mol NH3 are needed to form 44.8 liters of NO gas at STP?

A 2.0
B n/a
C 0.2
D 0.5

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Ответ:

ninaaforever

28.11.2020

Chemistry

centrifugation, boiling/heating , and long standing

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4 NH3 + 5 O2 ---> 4 NO + 6 H2O How many mol NH3 are needed to form 44.8 liters of NO gas at STP? A 2.0 B n/a C 0.2 D 0.5