justritegrl
16.04.2021 •
Chemistry
58. What is the temperature if 30.1 g of N, in a 1.00-L container is at a pressure of 25.2 atm? DUE TONIGHT. LINKS DONT WORK SO PLS SHOW WORK. THANK YOU SO MUCH
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Ответ:
14°C
Explanation:
In order to use the ideal gas law, you need the number of moles of N2 present.
30.1 g x (mol / 28.02 g) = 1.07 mol N2
Use the ideal gas law: PV = nRT
Now isolate for T(temperature) and plug in your other values:
T = PV / nR
T = (25.2 atm)(1.00 L) / (1.07 mol)(0.08206)
T = 287 K
T(°C) = 287 K - 273 K = 14°C
Therefore, the temperature is 14°C
Ответ:
No, cutting paper is a physical change. Meaning that it is still paper no matter how many times you cut it. its chemical properties have not changed and it is still paper. cutting it would just give you smaller pieces of paper.