A 0.3480 g sample of potassium hydrogen phthalate is dissolved in 100.0 mL of water. If 32.07 mL of sodium hydroxide solution are required to reach the equivalence point, what is the molarity of the sodium hydroxide solution
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Ответ:
Recall the following terms which is,
KHP is Potassium hydrogen phthalate
NaOH is Sodium Hydroxide
NaKP is molar mass
H20 is water
Explanation:
KHP + NaOH = NaKP + H2O
moles of KHP = 0.3480g / 204.22 g·mol−1 = .001704
these will react with the same number of moles of NaOH according to the equation
these are in 0.03207 L of solution
The molarity of the NaOH solution = 0.001704 mol / 0.03207 L = 0.0531 M
the water takes no part in the reaction and the quantity can be ignored
Ответ:
b
Explanation: