![gutierrezforlife8220](/avatars/41455.jpg)
gutierrezforlife8220
26.07.2020 •
Chemistry
A 10.0 L flask at 318 K contains a mixture of Ar and CH4 with a total pressure of 1.040 atm. If the mole fraction of Ar is 0.715, what is the mass percent of Ar?
Solved
Show answers
More tips
- F Food and Cooking Homemade French Fries: The Ultimate Guide...
- D Dating, Love, Relationships How Long Can Love Last?...
- A Auto and Moto Mastering One-Movement Parking: All You Need to Know...
- C Computers and Internet How to Properly Order Clothing from International Online Stores...
- H Health and Medicine Headache: A Comprehensive Guide to Treatment...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- A Auto and Moto Discovering the Leader: What is the Most Expensive Car in the World?...
- F Food and Cooking How to Quickly Put your Child to Sleep?...
- C Computers and Internet How to Create a Website for Free and Easy?...
- F Family and Home Parquet or laminate, which is better?...
Answers on questions: Chemistry
- C Chemistry Among the methods you researched, do you think there’s one method that’s effective in all situations? Explain your answer....
- C Chemistry WILL GIVE BRANLIEST WILL FOREVER BE GREATFUL EASY BUT I WAS TO LAZY TO LEARN 6. Which type mixture does not allow light to shine through? A) Ionic B) Solutions C)...
- C Chemistry A student on spring break is sitting at the beach laying in the hot sun. The student uses their handy thermometer to measure that the sand at the beach has increased...
- C Chemistry Given the formula 4f10, what does the 10 stand for?...
- C Chemistry Most plastics are made from oil or natural gas. One step in making plastics from these resources is called cracking. Cracking is a process that breaks down bigger...
- C Chemistry Each atom has 1 proton but the number of neutrons are different . What is it called...
- C Chemistry Chlorophyll is found in A. neither plant nor animal cells. B. animal cells. C. plant cells. D. plant and animal cells....
- C Chemistry Propose syntheses of acetals A and B from carbonyl compounds and alcohols. Draw the structures of the carbonyl compounds and the alcohols, and select the appropriate...
- C Chemistry Draw the structural formula of the MAJOR product formed by the alkene having the HIGHER reaction rate....
- C Chemistry 15 points right hector carried out an experiment to see if adding calcium powder to soil made plants grow taller. he took two potted plants and put calcium powder...
Ответ:
Explanation:
Hello,
In this case, given the temperature, volume and total pressure, we can compute the total moles by using the ideal gas equation:
Next, using the molar fraction of argon, we compute the moles of argon:
And the moles of methane:
Now, by using the molar masses of both argon and methane, we can compute the mass percent of argon:
Regards.
Ответ:
The percent yield is 99.9 %
Explanation:
Step 1: Data given
Mass of a sample Al2(SO4)3 = 500 grams
Mass of Ca(OH)2 = 450 grams
Mass of CaSO4 produced = 596 grams
Molar mass Al2(SO4)3 = 342.15 g/mol
Molar mass Ca(OH)2 = 74.09 g/mol
Step 2: The balanced equation
Al2(SO4)3 + 3Ca(OH)2 → 2Al(OH)3 + 3CaSO4
Step 3: Calculate moles
Moles = mass / molar mass
Moles Al2(SO4)3 = 500 grams / 342.15 g/mol
Moles Al2(SO4)3 = 1.46 moles
Moles Ca(OH)2 = 450 grams / 74.09 g/mol
Moles Ca(OH)2 = 6.07 moles
Step 4: Calculate the limiting reactant
For 1 mol Al2(SO4)3 we need 3 moles Ca(OH)2 to produce 2 moles Al(OH)3 and 3 moles CaSO4
Al2(SO4)3 is the limiting reactant. It will completely be consumed (1.46 moles). Ca(OH)2 is in excess. There will react 3*1.46 = 4.38 moles
There will remain 6.07 - 4.38 = 1.69 moles
Step 5: Calculate moles CaSO4
For 1 mol Al2(SO4)3 we need 3 moles Ca(OH)2 to produce 2 moles Al(OH)3 and 3 moles CaSO4
For 1.46 moles Al2(SO4)3 we'll have 3*1.46 moles = 4.38 moles CaSO4
Step 6: Calculate mass CaSO4
Mass CaSO4 = 4.38 moles * 136.14 g/mol
Mass CaSO4 = 596.3 grams
Step 7: Calculate percent yield
Percent yield = (actual yield / theoretical yield) * 100%
Percent yield = (596 grams / 596.3 grams ) *100 %
Percent yield = 99.9 %
The percent yield is 99.9 %