A 150 mL sample of hydrochloric acid (HCl) completely reacted with 60.0 mL of a 0.100 M NaOH solution. The equation for the reaction is given below. HCl + NaOH Right arrow. NaCl + H2O What was the original concentration of the HCl solution? 0.040 M 0.25 M 1.50 M 2.50 M
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Ответ:
0.040M
Explanation:
The following data were obtained from the question:
Volume of acid (Va) = 150mL
Volume of base (Vb) = 60mL
Molarity of base (Mb) = 0.1M
Molarity of acid (Ma) =..?
Next, the balanced equation for the reaction. This is given below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Finally, we shall determine the concentration of the acid, HCl as follow:
MaVa / MbVb = nA/nB
Ma x 150 / 0.1 x 60 = 1/1
Cross multiply to express in linear form
Ma x 150 = 0.1 x 60
Divide both side by 150
Ma = 0.1 x 60 / 150
Ma = 0.04M
Therefore, the concentration of the acid is 0.04M
Ответ:
26.8224 Meters per Second.