oranzajimenez
04.11.2021 •
Chemistry
A 152 g sample of ice at –37oC is heated until it turns into liquid water at 0oC. Find the change in heat content of the system.
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Ответ:
What do you mean? The Q is a bit vague
Ответ:
The change in heat content is
26,000 J
.
Explanation:
Use the following equation:
Q
=
m
c
Δ
T
,
where
Q
is heat energy in Joules,
m
is mass,
c
is specific heat capacity, and
Δ
T
is change in temperature,
(
T
final
−
T
initial
)
.
Organize your data
.
Given/Known
m
=
445 g
c
ice
=
2.03 J
g
⋅
∘
C
T
initial
=
−
58
∘
C
T
final
=
−
29
∘
C
Δ
T
=
−
29
∘
C
−
(
−
58
∘
C
)
=
29
∘
C
Explanation:
Ответ:
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