A 5.0g sample of Cu(NO3)2•nH2O is heated, and 3.9g of the anhydrous salt remains. what is the value for n?
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Ответ:
2.9
Explanation:
Molar mass of Cu(NO3)2 = 187.5 g/mol
Molar mass of water = 18.0 g/mol
%H2O = (5.0 g - 3.9 g) / 5.0 g X 100 (100 is to get percent) = (1.1 g) / 5.0 g X 100
= 22.0 %
% H2O = ( mass of H20 alone) / (mass of total hydrate)
0.22 = 18.0n / (18.0n + 187.5)
n = 2.9 = (about) 3
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