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finleymarch14
11.01.2021 •
Chemistry
A 7.298 g sample of copper reacts with oxygen, forming a copper oxide. The final mass of the copper oxide is 8.217 g. What is the formula of the copper oxide
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Ответ:
Cu2O
Explanation:
We get mass of Cu and O in copper oxide.
Cu = copper
O = Oxygen
Cu = 7.298g
Then the mass of o is given as
CuO - Cu
= 8.217 - 7.298
= 0.919g
Then we get the number of moles
n = m/M
m = mass
M = molar mass
M of Cu = 63.55g/mol
M of oxygen = 16g/mol
n(copper) = 7.298/63.55
= 0.1148mol
n(oxygen) = 0.919/16g
= 0.0574mol
From here we get the molar ratio
n(copper)/n(oxygen)
= 0.1148/0.0574
= 2/1
Cu:O = 2:1
Cu2O is therefore the formula of copper Oxide
Ответ:
Proton:
Positive
Found in Nucleus
Mass of 1 AMU
Neutron:
Neutral
Found in Nucleus
Mass of 1 AMU
Electron:
Negative
Found in orbitals
Mass of 0 AMU