A 750.0 mL solution contains 5.00 g of NaOH. If the molar mass of NaOH is 39.9969 g/mol, what is the molarity of the solution? (3 points)
A:0.0891 M NaOH
B:0.167 M NaOH
C:1.25 M NaOH
D:5.98 M NaOH

B

Molarity is defined as M=(m/mw)/L solution where M is molarity, m is weight, mw is molar weight and L is liters.

First we plug in the mass, which is 5, then divide by the molar weight of 39.9969 which can just be rounded to 40.

Then we convert 750mL to liters which would be 0.75 liters. The root "milli" is x10-3, therefore we convert it to become 0.75L.

Now we just solve the equation, 5/40/0.75 is 0.166 repeating decimal, or just 0.167 rounding to three significant digits.

What

Explanation: