A balloon is inflated to a volume of 7.0 L 7.0 L on a day when the atmospheric pressure is 765 mmHg. The next day, as a storm front arrives, the atmospheric pressure drops to 737 mmHg 737 mmHg . Assuming the temperature remains constant, what is the new volume of the balloon, in liters?
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Ответ:
The new volume is 7.27 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 7.0 L
The pressure = 765 mmHg = 765/760 atm = 1.00658 atm
The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737
The temperature remains constant
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒with P1 = the initial pressure in the balloon = 765 mmHg
⇒with V1 = the initial volume = 7.0L
⇒with P2 = the decreased pressure = 737 mmHg
⇒with V2 = the new volume = TO BE DETERMINED
765 mmHg * 7.0 L = 737 mmHG * V2
V2 = (765 mmHG * 7.0 L) / 737 mmHG
V2 = 7.27 L
The new volume is 7.27 L
Ответ:
Caravaggio (byname of Michelangelo Merisi) was a leading Italian painter of the late 16th and early 17th centuries who became famous for the intense and unsettling realism of his large-scale religious works as well as for his violent exploits—he committed murder—and volatile character.
Explanation: