A balloon that contains 1.50 L of air at 1.00 atm is taken underwater to a depth at which the pressure is 3.00 atm. Calculate the new volume of the balloon. Assume the temperature remains constant.

153

Step-by-step explanation:

Box 1:

180 = 124 + (5x + 11)

56 = 5x + 11

45 = 5x

x = 9

Box 2:

RT = QS

x + 9 = 2x - 5

x = 14

Box 3:

14x - 3 = 18x -19

16 = 4x

x = 4

Box 4:

180 = (9x - 8) + (7x - 4)

180 = 16x - 12

192 = 16x

x = 12

Box 5:

(6x + 34) = (12x - 8)

42 = 6x

x = 7

Box 6:

45 = 7x - 25

70 = 7x

x = 10

Box 7:

54 - x = 3x - 10

64 = 4x

x = 16

Box 8:

12x + 1 = 9x + 16

3x = 15

x = 5

Box 9:

3x + 2x - 5 = 90

5x - 5 = 90

5x = 85

x = 17

Final Code:

(9)(17) = 153