Chemistry: A chemist dissolves 581.1mg of pure perchloric acid in enough water to make up 150 ml of solution. Calculate the pH of the solution. Round your answer to significant decimal places.

A chemist dissolves 581.1mg of pure perchloric

Ответ:

simmonss1185

20.01.2022

Chemistry

The pH of the solution is 1.41

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of perchloric acid = 581.1 mg = 0.5811 g (Conversion factor: 1 g = 1000 mg)

Molar mass of perchloric acid = 100.5 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

$\text{Molarity of perchloric acid}=\frac{0.5811\times 1000}{100.5\times 150}\\\\\text{Molarity of perchloric acid}=0.0385M$

1 mole of perchloric acid produces 1 mole of H^+ ions and 1 mole of ClO_4^- ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

[H^+]=0.0385M

Putting values in above equation, we get:

$pH=-\log (0.0385)=1.41$

Hence, the pH of the solution is 1.41

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Ответ:

birdwithpurpleboots

10.08.2022

Chemistry

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

Explanation:

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A chemist dissolves 581.1mg of pure perchloric acid in enough water to make up 150 ml of solution. Calculate the pH of the solution. Round your answer to significant decimal places.

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