A chemist prepares a solution of calcium sulfate CaSO4 by measuring out 0.03g of calcium sulfate into a 150.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /molL of the chemist's calcium sulfate solution. Be sure your answer has the correct number of significant digits.

0.00147 Molar is the molarity of the solution.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

Mass of calcium sulfate = 0.03 g

Molar mass of calcium sulfate = 136 g/mol

Volume of the calcium sulfate = 150. mL = 0.150 L ( 1 L = 0.001 mL)

0.00147 Molar is the molarity of the solution.

Divide the mass of the water lost by the mass of hydrate and multiply by 100. The theoretical (actual) percent hydration (percent water) can be calculated from the formula of the hydrate by dividing the mass of water in one mole of the hydrate by the molar mass of the hydrate and multiplying by 100

Explanation:

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