a cylinder with a movable piston contains 250 cm3 air at 10°C. if the pressure is kept constant, at what temperature would you expect the volume to be 150 cm3?

T₂ = 169.89 K

Explanation:

Given data:

Initial volume = 250 cm³

Initial temperature = 10°C (10+273.15 K = 283.15 K)

Final temperature = ?

Final volume = 150 cm³

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 283.15 K × 150 cm³ /  250 cm³

T₂ = 42472.5 K. cm³  / 250 cm³

T₂ = 169.89 K

We are task to Convert Degree Celsius to Degree Fahrentheit and Kelvin.
To do this, we know that
Deg F=deg C(9/5)+32
By Subtituting the given formula and the required unit, we get
Deg F= 2966 deg C(9/5)+32
Symplifying further,
DegF=5338.8+32=5370.8 deg F
For Deg C to Kelvin
We got the formula,
K=degC+273.15=2966+273.15
Simplifying Further,
K=3239.15 K