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lilobekker5219
15.04.2020 •
Chemistry
A flexible container at an initial volume of 5.120 L contains 8.500 mol of gas.
More gas is then added to the container until it reaches a final volume of 18.10
L. Assuming the pressure and temperature of the gas remain constant,
calculate the total number of moles of gas in the container.
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Ответ:
30.05 mol
Explanation:
solving the proportion
V1 / n1 = V2 / n2
5.120 L 18.10 L
––––––––=––––––
8.500 mol x
x = 30.05 mol
Ответ:
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg
Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol
The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺
The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5
Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
= 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol
Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
= 0.031395 g
= 31.395 mg
≈ 31.4 mg