simmers123
24.03.2020 •
Chemistry
A galvanic cell is powered by the following redox reaction: Cl 2(g) + Mn 2 +(aq) + 2 H-On â 2 Cl-(aq) + MnO2(s) + 4 H + (aq) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half reaction that takes place at the cathode Write a balanced equation for the half- reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to 2 decimalEV places.
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Ответ:
2.59V
Explanation:
Cathode half reaction equation:
Cl2(g) + 2e > 2Cl-(aq)
Anode half reaction equation:
Mn^2+(aq) + 2H2O(l) > MnO2(s) + 2e + 4H+
E°cathode= 1.36V
E°anode= -1.23V
E°cell= E°cathode - E°anode
E°cell= 1.36 - (-1.23)
E°cell= 2.59V
Ответ: