Uhmjujiooo4220
23.10.2020 •
Chemistry
A gas at STP occupies 1.50 L. If the pressure drops to 0.75 atm and the temperature is raised to 300 K, what is the new volume?
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Ответ:
V₂ = 1.82 L
Explanation:
Given data:
Initial volume of gas = 1.50 L
Initial temperature = 273 K
Initial pressure = 1 atm
Final pressure = 0.75 atm
Final temperature = 300 K
Final volume = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 1.50 L × 273 K / 300 K ×0.75 atm
V₂ = 409.5 atm .L. K / 225 K.atm
V₂ = 1.82 L
Ответ:
14 _10 #sd × 13