A liquid is exposed to infrared radiation with a wavelength of 5.10×10−4 cm.
Assume that all the radiation is absorbed and converted to heat. How many photons are required for the liquid to absorb 42.75 J
of heat?
Solved
Show answers
More tips
- C Computers and Internet Clearing Cache: How to Speed Up Your Browser...
- S Style and Beauty How are artificial nails removed?...
- S Style and Beauty Secrets of Tying a Pareo: 5 Ways...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
Ответ:
1.1×10²¹ photon
Explanation:
Given data:
Wavelength of radiation = 5.10×10⁻⁴ cm
How many radiations required to liquid inorder to absorbed 42.75 J = ?
Solution:
First of all we will calculate the energy of radiation having 5.10×10⁻⁴ cm.
E = h.c/ λ
E = 6.63 ×10⁻³⁴ js × 3 ×10⁸ m/s / 0.051×10⁻⁴ m
E = 19.89 ×10⁻²⁶ j.m/ 0.051×10⁻⁴ m
E = 390 ×10⁻²² j
The energy of 1 photon with 5.10×10⁻⁴ cm. wavelength having 390 ×10⁻²² j energy.
1 photon × 42.75 J/390 ×10⁻²² j
0.11 ×10²²photon
1.1×10²¹ photon
Ответ: