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Chartwig1908
31.03.2020 •
Chemistry
A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, what mass of M (g) is contained in 329 g of the mineral?
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Ответ:
15.38 g is the mass for M in the 329 g of sample
Explanation:
Mineral's formula: MS
Our sample weighs 44.9 g
Mass of M: 2.1 g
Our new sample weighs 329 g
We may solve this by a rule of three:
44.9 g of sample contain 2.1 g of M
329 g of sample will contain (329 . 2.1) / 44.9 = 15.38 g
Ответ:
In a 329 grams mineral, we have 15.4 grams of metal M
Explanation:
Step 1: Data given
Mass of the sample = 44.9 grams
The mineral contains: 2.1 grams of M
Step 2: Calculate mass % of M
mass % of M = (mass M / total mass sample) * 100 %
mass % of M = (2.1 grams / 44.9 grams) *100 %
mass % of M = 4.677 %
Step 3: Calculate the mass of M in a 329 grams
Mass % = (4.677 grams / 100 % ) * 329 grams
Mass % = 0.04677 * 329 grams
Mass % = 15.4 grams
In a 329 grams mineral, we have 15.4 grams of metal M
Ответ: