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25.11.2020 •
Chemistry
A mixture of Xe, Kr and Ar has a total pressure of 6.70 atm. What is the mole fraction of Kr if the partial pressure of Xe is 1.60 atm and that of Ar is 2.80 atm.
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Ответ:
0.343
Explanation:
Step 1: Given data
Total pressure of the gaseous mixture (P): 6.70 atmPartial pressure of Xe (pXe): 1.60 atmPartial pressure of Ar (pAr): 2.80 atmStep 2: Calculate the partial pressure of Kr
The total pressure of the mixture is equal to the sum of the partial pressures of the individual gases.
P = pXe + pAr + pKr
pKr = P - pXe - pAr
pKr = 6.70 atm - 1.60 atm - 2.80 atm
pKr = 2.30 atm
Step 3: Calculate the mole fraction of Kr
We will use the following expression.
X(Kr) = pKr/P
X(Kr) = 2.30 atm/6.70 atm
X(Kr) = 0.343
Ответ:
open system
Explanation: