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jade611135
27.06.2020 •
Chemistry
A plastic bottle is closed outdoors on a cold day when the temperature is −15.0°C and is later brought inside where the temperature is 21.5°C. What is the pressure of the air in the bottle after it reaches room temperature, assuming the air in the bottle was at a pressure of 1.00 atm upon reaching thermal equilibrium with the outdoor temperature?
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Ответ:
Pressure = 1.14 atm
Explanation:
Hello,
This question requires us to calculate the final pressure of the bottle after thermal equilibrium.
This is a direct application of pressure law which states that in a fixed mass of gas, the pressure of a given gas is directly proportional to its temperature, provided that volume remains constant.
Mathematically, what this implies is
P = kT k = P / T
P1 / T1 = P2 / T2 = P3 / T3 == Pn / Tn
P1 / T1 = P2 / T2
P1 = 1.0atm
T1 = -15°C = (-15 + 273.15)K = 258.15K
P2 = ?
T2 = 21.5°C = (21.5 + 273.15)K = 294.65K
P1 / T1 = P2 / T2
P2 = (P1 × T2) / T1
P2 = (1.0 × 294.65) / 258.15
P2 = 1.14atm
The pressure of the gas after attaining equilibrium is 1.14atm
Ответ:
The world population is expected to reach 9 billion by the year 2050.
NOT:
a. 4 billion
c. 7 billion
b. 6 billion