A ring weighing 9.45 g is placed in a graduated cylinder containing 25.3 mL of water. After the ring is added to the cylinder the water rises to 27.4 mL. What metal is the ring made out of? Assume the ring is a single metal.

Titanium metal.

Explanation:

Mass of ring = 9.45 g

Initial Volume = 25.3 mL

Final Volume = 27.4 mL

Volume of ring = 27.4 - 25.3 = 2.1mL

Density = Mass / Volume

Density = 9.45 / 2.1

Density = 4.5g/ml

Since, the ring is a single metal, we look for the metal that has a density of 4.5g/ml. This metal is the Titanium metal.

a) rate law1 = k[NO2]²

b) rate law2 = k[NO][O3]

Explanation:

NO2(g) + CO(g) → NO(g) + CO2(g)

NO(g) + O3(g) → NO2(g) + O2(g)

When [NO2] in reaction 1 is doubled, the reaction quadruples

Rxn is second order.

rate law1= [NO2]^a [CO]^b

rate law1= [NO2]² [CO]^0

rate law1 = k[NO2]²

When [NO] in reaction 2 is doubled, the rate doubles.

Rxn is first order

The ratio is 1:1

this makes the rate law2 = k[NO][O3]