Chemistry: A sample of Kr gas is observed to effuse through a porous barrier in 3.79 minutes. Under the same conditions, the same number of moles of an unknown gas requires 2.66 minutes to effuse through the same barrier. The molar mass of the unknown gas is g/mol.

Move or rotate as well since they stay in place and we move....

A sample of Kr gas is observed to effuse through - id13652248, nesharhodes23p965te

katielloyd

07.07.2021

M'=41.3g/mol

Explanation:

From the question we are told that:

Time Through first barrier T_1=3.79min

Time Through second barrier T_2=2.66min

Generally the Grahams Law equation for time of diffusion is mathematically given by

$T=K\sqrt{M}$

Where

M=Mass Number of Kr

M=83.8

Therefore

${T}{\sqrt{M}={T}{\sqrt{M'}$

${3.79}{\sqrt{83.8}={2.66}{\sqrt{M'}$

M'=0.645

M'=41.3g/mol

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